Base | Representation |
---|---|
bin | 1001001001110111010001… |
… | …01001101110000111111111 |
3 | 2122021102100200012101022222 |
4 | 10210323220221232013333 |
5 | 10114302441204444444 |
6 | 110451352141155555 |
7 | 4145232065540312 |
oct | 444735051560777 |
9 | 78242320171288 |
10 | 20130119999999 |
11 | 6461154a48a19 |
12 | 231142855bbbb |
13 | b30353cb2489 |
14 | 4d8435642979 |
15 | 24d96d4eeeee |
hex | 124ee8a6e1ff |
20130119999999 has 2 divisors, whose sum is σ = 20130120000000. Its totient is φ = 20130119999998.
The previous prime is 20130119999963. The next prime is 20130120000083. The reversal of 20130119999999 is 99999991103102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20130119999999 is a prime.
20130119999999 is a modest number, since divided by 9999999 gives 2013011 as remainder.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130119999929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065059999999 + 10065060000000.
It is an arithmetic number, because the mean of its divisors is an integer number (10065060000000).
Almost surely, 220130119999999 is an apocalyptic number.
20130119999999 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130119999999 is an equidigital number, since it uses as much as digits as its factorization.
20130119999999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28697814, while the sum is 71.
The spelling of 20130119999999 in words is "twenty trillion, one hundred thirty billion, one hundred nineteen million, nine hundred ninety-nine thousand, nine hundred ninety-nine".
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