Base | Representation |
---|---|
bin | 111011111111100… |
… | …0010000010110111 |
3 | 12012021211121112121 |
4 | 1313333002002313 |
5 | 13110312342101 |
6 | 531425500411 |
7 | 100612215043 |
oct | 16777020267 |
9 | 5167747477 |
10 | 2013012151 |
11 | 943324907 |
12 | 4821a1707 |
13 | 261081c67 |
14 | 1514c5023 |
15 | bbad30a1 |
hex | 77fc20b7 |
2013012151 has 2 divisors, whose sum is σ = 2013012152. Its totient is φ = 2013012150.
The previous prime is 2013012101. The next prime is 2013012163. The reversal of 2013012151 is 1512103102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013012151 - 213 = 2013003959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013012101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506075 + 1006506076.
It is an arithmetic number, because the mean of its divisors is an integer number (1006506076).
Almost surely, 22013012151 is an apocalyptic number.
2013012151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013012151 is an equidigital number, since it uses as much as digits as its factorization.
2013012151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
The square root of 2013012151 is about 44866.6039610755. The cubic root of 2013012151 is about 1262.6475260210.
Adding to 2013012151 its reverse (1512103102), we get a palindrome (3525115253).
The spelling of 2013012151 in words is "two billion, thirteen million, twelve thousand, one hundred fifty-one".
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