Base | Representation |
---|---|
bin | 11101010010110000111… |
… | …000001101100001111111 |
3 | 21010102221021122010011022 |
4 | 131102300320031201333 |
5 | 230440122112020111 |
6 | 4140433130014355 |
7 | 265302214356431 |
oct | 35226070154177 |
9 | 7112837563138 |
10 | 2013012220031 |
11 | 706793a1233a |
12 | 2861758773bb |
13 | 117a98324257 |
14 | 6d604aba651 |
15 | 3756a5452db |
hex | 1d4b0e0d87f |
2013012220031 has 2 divisors, whose sum is σ = 2013012220032. Its totient is φ = 2013012220030.
The previous prime is 2013012219997. The next prime is 2013012220057. The reversal of 2013012220031 is 1300222103102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013012220031 - 222 = 2013008025727 is a prime.
It is a super-2 number, since 2×20130122200312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013012219991 and 2013012220009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013012225031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506110015 + 1006506110016.
It is an arithmetic number, because the mean of its divisors is an integer number (1006506110016).
Almost surely, 22013012220031 is an apocalyptic number.
2013012220031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013012220031 is an equidigital number, since it uses as much as digits as its factorization.
2013012220031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2013012220031 its reverse (1300222103102), we get a palindrome (3313234323133).
The spelling of 2013012220031 in words is "two trillion, thirteen billion, twelve million, two hundred twenty thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •