Base | Representation |
---|---|
bin | 1001001001110111010001… |
… | …10101100011011110001011 |
3 | 2122021102100220000222121021 |
4 | 10210323220311203132023 |
5 | 10114302443003231331 |
6 | 110451352331453311 |
7 | 4145232134110312 |
oct | 444735065433613 |
9 | 78242326028537 |
10 | 20130123102091 |
11 | 6461156777632 |
12 | 23114295b7237 |
13 | b3035482a432 |
14 | 4d8435c0d279 |
15 | 24d96d914211 |
hex | 124ee8d6378b |
20130123102091 has 2 divisors, whose sum is σ = 20130123102092. Its totient is φ = 20130123102090.
The previous prime is 20130123101989. The next prime is 20130123102101. The reversal of 20130123102091 is 19020132103102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130123102091 - 217 = 20130122971019 is a prime.
It is a super-2 number, since 2×201301231020912 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20130123103091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065061551045 + 10065061551046.
It is an arithmetic number, because the mean of its divisors is an integer number (10065061551046).
Almost surely, 220130123102091 is an apocalyptic number.
20130123102091 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130123102091 is an equidigital number, since it uses as much as digits as its factorization.
20130123102091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 20130123102091 its reverse (19020132103102), we get a palindrome (39150255205193).
The spelling of 20130123102091 in words is "twenty trillion, one hundred thirty billion, one hundred twenty-three million, one hundred two thousand, ninety-one".
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