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2013013321200 = 2432527177744953
BaseRepresentation
bin11101010010110000111…
…100011010010111110000
321010102221100201001200100
4131102300330122113300
5230440122402234300
64140433205352400
7265302226624020
oct35226074322760
97112840631610
102013013321200
117067945a46a2
12286176108700
13117a9861b52b
146d604cc5a80
153756a6b1700
hex1d4b0f1a5f0

2013013321200 has 360 divisors, whose sum is σ = 7988345220128. Its totient is φ = 459848171520.

The previous prime is 2013013321133. The next prime is 2013013321201. The reversal of 2013013321200 is 21233103102.

2013013321200 is a `hidden beast` number, since 2 + 0 + 130 + 1 + 332 + 1 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (360).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013013321201) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 44757924 + ... + 44802876.

Almost surely, 22013013321200 is an apocalyptic number.

2013013321200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013013321200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3994172610064).

2013013321200 is an abundant number, since it is smaller than the sum of its proper divisors (5975331898928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013013321200 is a wasteful number, since it uses less digits than its factorization.

2013013321200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46761 (or 46747 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 2013013321200 its reverse (21233103102), we get a palindrome (2034246424302).

The spelling of 2013013321200 in words is "two trillion, thirteen billion, thirteen million, three hundred twenty-one thousand, two hundred".