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201301400114 = 2100650700057
BaseRepresentation
bin1011101101111001111…
…1111001101000110010
3201020121001002122211122
42323132133321220302
511244231124300424
6232250535342242
720354302445303
oct2733637715062
9636531078748
10201301400114
117840a435391
123301b521982
1315ca0b27509
149a58c887aa
15538283e45e
hex2ede7f9a32

201301400114 has 4 divisors (see below), whose sum is σ = 301952100174. Its totient is φ = 100650700056.

The previous prime is 201301400071. The next prime is 201301400117. The reversal of 201301400114 is 411004103102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 198276950089 + 3024450025 = 445283^2 + 54995^2 .

It is a junction number, because it is equal to n+sod(n) for n = 201301400092 and 201301400101.

It is not an unprimeable number, because it can be changed into a prime (201301400117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50325350027 + ... + 50325350030.

Almost surely, 2201301400114 is an apocalyptic number.

201301400114 is a deficient number, since it is larger than the sum of its proper divisors (100650700060).

201301400114 is a wasteful number, since it uses less digits than its factorization.

201301400114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100650700059.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 201301400114 its reverse (411004103102), we get a palindrome (612305503216).

The spelling of 201301400114 in words is "two hundred one billion, three hundred one million, four hundred thousand, one hundred fourteen".

Divisors: 1 2 100650700057 201301400114