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20130201013211 is a prime number
BaseRepresentation
bin1001001001110111011010…
…11110110000101111011011
32122021102120022122021120022
410210323231132300233123
510114303122424410321
6110451404153421055
74145234101253402
oct444735536605733
978242508567508
1020130201013211
116461196751393
12231144b70a78b
13b30367a08aa3
144d84422d0639
1524d9756a3dab
hex124eed7b0bdb

20130201013211 has 2 divisors, whose sum is σ = 20130201013212. Its totient is φ = 20130201013210.

The previous prime is 20130201013183. The next prime is 20130201013213. The reversal of 20130201013211 is 11231010203102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20130201013211 - 26 = 20130201013147 is a prime.

Together with 20130201013213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20130201013211.

It is not a weakly prime, because it can be changed into another prime (20130201013213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100506605 + 10065100506606.

It is an arithmetic number, because the mean of its divisors is an integer number (10065100506606).

Almost surely, 220130201013211 is an apocalyptic number.

20130201013211 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130201013211 is an equidigital number, since it uses as much as digits as its factorization.

20130201013211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 20130201013211 its reverse (11231010203102), we get a palindrome (31361211216313).

The spelling of 20130201013211 in words is "twenty trillion, one hundred thirty billion, two hundred one million, thirteen thousand, two hundred eleven".