Base | Representation |
---|---|
bin | 1001001001110111011111… |
… | …10111010101110111001111 |
3 | 2122021102200002220101102111 |
4 | 10210323233313111313033 |
5 | 10114303213144324101 |
6 | 110451412143004451 |
7 | 4145235065242435 |
oct | 444735767256717 |
9 | 78242602811374 |
10 | 20130241011151 |
11 | 6461207290437 |
12 | 2311460b99727 |
13 | b303730a16cb |
14 | 4d8447742d55 |
15 | 24d978e55251 |
hex | 124eefdd5dcf |
20130241011151 has 2 divisors, whose sum is σ = 20130241011152. Its totient is φ = 20130241011150.
The previous prime is 20130241011059. The next prime is 20130241011169. The reversal of 20130241011151 is 15111014203102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130241011151 - 239 = 19580485197263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130241011851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065120505575 + 10065120505576.
It is an arithmetic number, because the mean of its divisors is an integer number (10065120505576).
Almost surely, 220130241011151 is an apocalyptic number.
20130241011151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130241011151 is an equidigital number, since it uses as much as digits as its factorization.
20130241011151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 20130241011151 its reverse (15111014203102), we get a palindrome (35241255214253).
The spelling of 20130241011151 in words is "twenty trillion, one hundred thirty billion, two hundred forty-one million, eleven thousand, one hundred fifty-one".
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