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20130281 is a prime number
BaseRepresentation
bin100110011001…
…0100111101001
31101212201112222
41030302213221
520123132111
61555243425
7333050603
oct114624751
941781488
1020130281
11103aa1a6
1268a9575
13422a812
142960173
151b797db
hex13329e9

20130281 has 2 divisors, whose sum is σ = 20130282. Its totient is φ = 20130280.

The previous prime is 20130251. The next prime is 20130289. The reversal of 20130281 is 18203102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20106256 + 24025 = 4484^2 + 155^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130281 - 210 = 20129257 is a prime.

It is a super-2 number, since 2×201302812 = 810456426277922, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20130289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065140 + 10065141.

It is an arithmetic number, because the mean of its divisors is an integer number (10065141).

Almost surely, 220130281 is an apocalyptic number.

It is an amenable number.

20130281 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130281 is an equidigital number, since it uses as much as digits as its factorization.

20130281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 20130281 is about 4486.6781698713. The cubic root of 20130281 is about 272.0298815571.

Adding to 20130281 its reverse (18203102), we get a palindrome (38333383).

The spelling of 20130281 in words is "twenty million, one hundred thirty thousand, two hundred eighty-one".