Base | Representation |
---|---|
bin | 11101010010110010000… |
… | …000010001111000101000 |
3 | 21010102222121011221101110 |
4 | 131102302000101320220 |
5 | 230440141431042412 |
6 | 4140435042550320 |
7 | 265302534062640 |
oct | 35226200217050 |
9 | 7112877157343 |
10 | 2013031112232 |
11 | 7067a3646328 |
12 | 2861800683a0 |
13 | 117a9c20a37a |
14 | 6d6073d7520 |
15 | 3756c027d3c |
hex | 1d4b2011e28 |
2013031112232 has 32 divisors (see below), whose sum is σ = 5751517464000. Its totient is φ = 575151746304.
The previous prime is 2013031112201. The next prime is 2013031112293. The reversal of 2013031112232 is 2322111303102.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 2013031112199 and 2013031112208.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5991163857 + ... + 5991164192.
It is an arithmetic number, because the mean of its divisors is an integer number (179734920750).
Almost surely, 22013031112232 is an apocalyptic number.
It is an amenable number.
2013031112232 is an abundant number, since it is smaller than the sum of its proper divisors (3738486351768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013031112232 is a wasteful number, since it uses less digits than its factorization.
2013031112232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11982328065 (or 11982328061 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 2013031112232 its reverse (2322111303102), we get a palindrome (4335142415334).
The spelling of 2013031112232 in words is "two trillion, thirteen billion, thirty-one million, one hundred twelve thousand, two hundred thirty-two".
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