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201303443401009 is a prime number
BaseRepresentation
bin101101110001010110011100…
…001111000110100100110001
3222101202102101002100101222021
4231301112130033012210301
5202341123423002313014
61552045305241111441
760254456662365205
oct5561263417064461
9871672332311867
10201303443401009
11591613469146a4
121a6b1b57a88581
138842aaa8969c1
14379d1d2636b05
151841570441624
hexb7159c3c6931

201303443401009 has 2 divisors, whose sum is σ = 201303443401010. Its totient is φ = 201303443401008.

The previous prime is 201303443400989. The next prime is 201303443401037. The reversal of 201303443401009 is 900104344303102.

201303443401009 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199508647311009 + 1794796090000 = 14124753^2 + 1339700^2 .

It is a cyclic number.

It is not a de Polignac number, because 201303443401009 - 25 = 201303443400977 is a prime.

It is not a weakly prime, because it can be changed into another prime (201303443501009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651721700504 + 100651721700505.

It is an arithmetic number, because the mean of its divisors is an integer number (100651721700505).

Almost surely, 2201303443401009 is an apocalyptic number.

It is an amenable number.

201303443401009 is a deficient number, since it is larger than the sum of its proper divisors (1).

201303443401009 is an equidigital number, since it uses as much as digits as its factorization.

201303443401009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 34.

The spelling of 201303443401009 in words is "two hundred one trillion, three hundred three billion, four hundred forty-three million, four hundred one thousand, nine".