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20130403417 is a prime number
BaseRepresentation
bin10010101111110111…
…011001010001011001
31220221220220110002221
4102233313121101121
5312211340402132
613125304224041
71311564414535
oct225767312131
956856813087
1020130403417
1185a00a7043
123a9976b021
131b8a704c17
14d8d74cbc5
157cc428e97
hex4afdd9459

20130403417 has 2 divisors, whose sum is σ = 20130403418. Its totient is φ = 20130403416.

The previous prime is 20130403339. The next prime is 20130403441. The reversal of 20130403417 is 71430403102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20112628761 + 17774656 = 141819^2 + 4216^2 .

It is a cyclic number.

It is not a de Polignac number, because 20130403417 - 27 = 20130403289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20130403391 and 20130403400.

It is not a weakly prime, because it can be changed into another prime (20130403457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065201708 + 10065201709.

It is an arithmetic number, because the mean of its divisors is an integer number (10065201709).

Almost surely, 220130403417 is an apocalyptic number.

It is an amenable number.

20130403417 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130403417 is an equidigital number, since it uses as much as digits as its factorization.

20130403417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 20130403417 its reverse (71430403102), we get a palindrome (91560806519).

The spelling of 20130403417 in words is "twenty billion, one hundred thirty million, four hundred three thousand, four hundred seventeen".