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2013041430497 is a prime number
BaseRepresentation
bin11101010010110010100…
…111101000111111100001
321010110000022121011101102
4131102302213220333201
5230440202101233442
64140440052044145
7265303020556226
oct35226247507741
97113008534342
102013041430497
117067a9453619
12286183603655
13117aa13b0a56
146d60892194d
153756cdb5232
hex1d4b29e8fe1

2013041430497 has 2 divisors, whose sum is σ = 2013041430498. Its totient is φ = 2013041430496.

The previous prime is 2013041430457. The next prime is 2013041430539. The reversal of 2013041430497 is 7940341403102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1588668659776 + 424372770721 = 1260424^2 + 651439^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013041430497 - 234 = 1995861561313 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2013041430497.

It is not a weakly prime, because it can be changed into another prime (2013041430457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006520715248 + 1006520715249.

It is an arithmetic number, because the mean of its divisors is an integer number (1006520715249).

Almost surely, 22013041430497 is an apocalyptic number.

It is an amenable number.

2013041430497 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013041430497 is an equidigital number, since it uses as much as digits as its factorization.

2013041430497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 38.

Adding to 2013041430497 its reverse (7940341403102), we get a palindrome (9953382833599).

The spelling of 2013041430497 in words is "two trillion, thirteen billion, forty-one million, four hundred thirty thousand, four hundred ninety-seven".