Base | Representation |
---|---|
bin | 1001001001111000111101… |
… | …11001001000110010101001 |
3 | 2122021111201002112201210221 |
4 | 10210330132321020302221 |
5 | 10114311322140323144 |
6 | 110452022330010041 |
7 | 4145263455522616 |
oct | 444743671106251 |
9 | 78244632481727 |
10 | 20131030011049 |
11 | 6461581698771 |
12 | 2311641276921 |
13 | b3046a6a2759 |
14 | 4d84c044750d |
15 | 24d9c3357d84 |
hex | 124f1ee48ca9 |
20131030011049 has 2 divisors, whose sum is σ = 20131030011050. Its totient is φ = 20131030011048.
The previous prime is 20131030011013. The next prime is 20131030011121. The reversal of 20131030011049 is 94011003013102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17381336442649 + 2749693568400 = 4169093^2 + 1658220^2 .
It is a cyclic number.
It is not a de Polignac number, because 20131030011049 - 211 = 20131030009001 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131030015049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065515005524 + 10065515005525.
It is an arithmetic number, because the mean of its divisors is an integer number (10065515005525).
Almost surely, 220131030011049 is an apocalyptic number.
It is an amenable number.
20131030011049 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131030011049 is an equidigital number, since it uses as much as digits as its factorization.
20131030011049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 20131030011049 in words is "twenty trillion, one hundred thirty-one billion, thirty million, eleven thousand, forty-nine".
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