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20131031301233 is a prime number
BaseRepresentation
bin1001001001111000111101…
…11110000011110001110001
32122021111201011222021121112
410210330132332003301301
510114311323003114413
6110452022413403105
74145263502505236
oct444743676036161
978244634867545
1020131031301233
11646158239a036
122311641799495
13b3046aa34a88
144d84c06a178d
1524d9c35102a8
hex124f1ef83c71

20131031301233 has 2 divisors, whose sum is σ = 20131031301234. Its totient is φ = 20131031301232.

The previous prime is 20131031301209. The next prime is 20131031301253. The reversal of 20131031301233 is 33210313013102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17276259486784 + 2854771814449 = 4156472^2 + 1689607^2 .

It is a cyclic number.

It is not a de Polignac number, because 20131031301233 - 228 = 20130762865777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20131031301199 and 20131031301208.

It is not a weakly prime, because it can be changed into another prime (20131031301203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065515650616 + 10065515650617.

It is an arithmetic number, because the mean of its divisors is an integer number (10065515650617).

Almost surely, 220131031301233 is an apocalyptic number.

It is an amenable number.

20131031301233 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131031301233 is an equidigital number, since it uses as much as digits as its factorization.

20131031301233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 20131031301233 its reverse (33210313013102), we get a palindrome (53341344314335).

The spelling of 20131031301233 in words is "twenty trillion, one hundred thirty-one billion, thirty-one million, three hundred one thousand, two hundred thirty-three".