Base | Representation |
---|---|
bin | 11101010010110110010… |
… | …110101101001011100011 |
3 | 21010110011200112002212121 |
4 | 131102312112231023203 |
5 | 230440314122200232 |
6 | 4140450211205111 |
7 | 265304411342314 |
oct | 35226626551343 |
9 | 7113150462777 |
10 | 2013104100067 |
11 | 706830868155 |
12 | 2861a05a6797 |
13 | 117ab1383b38 |
14 | 6d612d9660b |
15 | 37573643d97 |
hex | 1d4b65ad2e3 |
2013104100067 has 2 divisors, whose sum is σ = 2013104100068. Its totient is φ = 2013104100066.
The previous prime is 2013104100043. The next prime is 2013104100167. The reversal of 2013104100067 is 7600014013102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013104100067 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013104100167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552050033 + 1006552050034.
It is an arithmetic number, because the mean of its divisors is an integer number (1006552050034).
Almost surely, 22013104100067 is an apocalyptic number.
2013104100067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013104100067 is an equidigital number, since it uses as much as digits as its factorization.
2013104100067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2013104100067 its reverse (7600014013102), we get a palindrome (9613118113169).
The spelling of 2013104100067 in words is "two trillion, thirteen billion, one hundred four million, one hundred thousand, sixty-seven".
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