Base | Representation |
---|---|
bin | 111011111111101… |
… | …1000101101010111 |
3 | 12012022000022212211 |
4 | 1313333120231113 |
5 | 13110323324413 |
6 | 531431454251 |
7 | 100613052511 |
oct | 16777305527 |
9 | 5168008784 |
10 | 2013104983 |
11 | 94338862a |
12 | 482227387 |
13 | 2610b52a6 |
14 | 15150abb1 |
15 | bbb0083d |
hex | 77fd8b57 |
2013104983 has 2 divisors, whose sum is σ = 2013104984. Its totient is φ = 2013104982.
The previous prime is 2013104909. The next prime is 2013105011. The reversal of 2013104983 is 3894013102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013104983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013104183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552491 + 1006552492.
It is an arithmetic number, because the mean of its divisors is an integer number (1006552492).
Almost surely, 22013104983 is an apocalyptic number.
2013104983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013104983 is an equidigital number, since it uses as much as digits as its factorization.
2013104983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The square root of 2013104983 is about 44867.6384825411. The cubic root of 2013104983 is about 1262.6669351262. Note that the first 3 decimals are identical.
The spelling of 2013104983 in words is "two billion, thirteen million, one hundred four thousand, nine hundred eighty-three".
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