2013105004081 has 2 divisors, whose sum is σ = 2013105004082. Its totient is φ = 2013105004080.

The previous prime is 2013105004067. The next prime is 2013105004093. The reversal of 2013105004081 is 1804005013102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199156403600 + 813948600481 = 1095060^2 + 902191^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013105004081 - 2¹¹ = 2013105002033 is a prime.

It is a super-2 number, since 2×2013105004081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2013105004051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006552502040 + 1006552502041.

It is an arithmetic number, because the mean of its divisors is an integer number (1006552502041).

Almost surely, 2^{2013105004081} is an apocalyptic number.

It is an amenable number.

2013105004081 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013105004081 is an equidigital number, since it uses as much as digits as its factorization.

2013105004081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

The spelling of 2013105004081 in words is "two trillion, thirteen billion, one hundred five million, four thousand, eighty-one".