Base | Representation |
---|---|
bin | 11101010010110110101… |
… | …101101011101011110001 |
3 | 21010110012002212010010102 |
4 | 131102312231223223301 |
5 | 230440322142420444 |
6 | 4140450544242145 |
7 | 265304513466521 |
oct | 35226655535361 |
9 | 7113162763112 |
10 | 2013110123249 |
11 | 706834201495 |
12 | 2861a2610355 |
13 | 117ab26b2554 |
14 | 6d613ac3681 |
15 | 37573e3384e |
hex | 1d4b6b6baf1 |
2013110123249 has 2 divisors, whose sum is σ = 2013110123250. Its totient is φ = 2013110123248.
The previous prime is 2013110123083. The next prime is 2013110123287. The reversal of 2013110123249 is 9423210113102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1395835917025 + 617274206224 = 1181455^2 + 785668^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013110123249 - 220 = 2013109074673 is a prime.
It is a super-2 number, since 2×20131101232492 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2013110122249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006555061624 + 1006555061625.
It is an arithmetic number, because the mean of its divisors is an integer number (1006555061625).
Almost surely, 22013110123249 is an apocalyptic number.
It is an amenable number.
2013110123249 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013110123249 is an equidigital number, since it uses as much as digits as its factorization.
2013110123249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 2013110123249 in words is "two trillion, thirteen billion, one hundred ten million, one hundred twenty-three thousand, two hundred forty-nine".
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