Base | Representation |
---|---|
bin | 11101010010110110101… |
… | …101101011101001001011 |
3 | 21010110012002212002220021 |
4 | 131102312231223221023 |
5 | 230440322142414313 |
6 | 4140450544241311 |
7 | 265304513466163 |
oct | 35226655535113 |
9 | 7113162762807 |
10 | 2013110123083 |
11 | 706834201354 |
12 | 2861a2610237 |
13 | 117ab26b2457 |
14 | 6d613ac35a3 |
15 | 37573e3378d |
hex | 1d4b6b6ba4b |
2013110123083 has 2 divisors, whose sum is σ = 2013110123084. Its totient is φ = 2013110123082.
The previous prime is 2013110123071. The next prime is 2013110123249. The reversal of 2013110123083 is 3803210113102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013110123083 is a prime.
It is a super-2 number, since 2×20131101230832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2013110123383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006555061541 + 1006555061542.
It is an arithmetic number, because the mean of its divisors is an integer number (1006555061542).
Almost surely, 22013110123083 is an apocalyptic number.
2013110123083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013110123083 is an equidigital number, since it uses as much as digits as its factorization.
2013110123083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 2013110123083 its reverse (3803210113102), we get a palindrome (5816320236185).
The spelling of 2013110123083 in words is "two trillion, thirteen billion, one hundred ten million, one hundred twenty-three thousand, eighty-three".
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