Base | Representation |
---|---|
bin | 10010101111111010… |
… | …000110100001011001 |
3 | 1220221222020111112121 |
4 | 102233322012201121 |
5 | 312212031104144 |
6 | 13125331341241 |
7 | 1311603431455 |
oct | 225772064131 |
9 | 56858214477 |
10 | 20131113049 |
11 | 85a0541213 |
12 | 3a99a51821 |
13 | 1b8a8c2c18 |
14 | d8d895665 |
15 | 7cc519384 |
hex | 4afe86859 |
20131113049 has 2 divisors, whose sum is σ = 20131113050. Its totient is φ = 20131113048.
The previous prime is 20131113011. The next prime is 20131113053. The reversal of 20131113049 is 94031113102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18628155225 + 1502957824 = 136485^2 + 38768^2 .
It is a cyclic number.
It is not a de Polignac number, because 20131113049 - 211 = 20131111001 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131113749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065556524 + 10065556525.
It is an arithmetic number, because the mean of its divisors is an integer number (10065556525).
Almost surely, 220131113049 is an apocalyptic number.
It is an amenable number.
20131113049 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131113049 is an equidigital number, since it uses as much as digits as its factorization.
20131113049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 20131113049 in words is "twenty billion, one hundred thirty-one million, one hundred thirteen thousand, forty-nine".
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