Base | Representation |
---|---|
bin | 10010101111111010… |
… | …001010110101010111 |
3 | 1220221222021101202202 |
4 | 102233322022311113 |
5 | 312212032140321 |
6 | 13125331555115 |
7 | 1311603534116 |
oct | 225772126527 |
9 | 56858241682 |
10 | 20131130711 |
11 | 85a055350a |
12 | 3a99a5ba9b |
13 | 1b8a8cac83 |
14 | d8d89bc7d |
15 | 7cc51e70b |
hex | 4afe8ad57 |
20131130711 has 2 divisors, whose sum is σ = 20131130712. Its totient is φ = 20131130710.
The previous prime is 20131130689. The next prime is 20131130801. The reversal of 20131130711 is 11703113102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20131130711 - 222 = 20126936407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131135711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065565355 + 10065565356.
It is an arithmetic number, because the mean of its divisors is an integer number (10065565356).
Almost surely, 220131130711 is an apocalyptic number.
20131130711 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131130711 is an equidigital number, since it uses as much as digits as its factorization.
20131130711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 20131130711 its reverse (11703113102), we get a palindrome (31834243813).
The spelling of 20131130711 in words is "twenty billion, one hundred thirty-one million, one hundred thirty thousand, seven hundred eleven".
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