Base | Representation |
---|---|
bin | 11101010010110110111… |
… | …001011011010110101011 |
3 | 21010110012022122112111121 |
4 | 131102312321123112223 |
5 | 230440323434431331 |
6 | 4140451134240111 |
7 | 265304551611655 |
oct | 35226671332653 |
9 | 7113168575447 |
10 | 2013113202091 |
11 | 706835a14692 |
12 | 2861a3656037 |
13 | 117ab321ca54 |
14 | 6d6142856d5 |
15 | 37574340c11 |
hex | 1d4b6e5b5ab |
2013113202091 has 2 divisors, whose sum is σ = 2013113202092. Its totient is φ = 2013113202090.
The previous prime is 2013113202071. The next prime is 2013113202137. The reversal of 2013113202091 is 1902023113102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013113202091 - 27 = 2013113201963 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013113202071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006556601045 + 1006556601046.
It is an arithmetic number, because the mean of its divisors is an integer number (1006556601046).
Almost surely, 22013113202091 is an apocalyptic number.
2013113202091 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013113202091 is an equidigital number, since it uses as much as digits as its factorization.
2013113202091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 2013113202091 its reverse (1902023113102), we get a palindrome (3915136315193).
The spelling of 2013113202091 in words is "two trillion, thirteen billion, one hundred thirteen million, two hundred two thousand, ninety-one".
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