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2013114193 is a prime number
BaseRepresentation
bin111011111111101…
…1010111101010001
312012022000210111221
41313333122331101
513110324123233
6531432005041
7100613121406
oct16777327521
95168023457
102013114193
11943394542
12482230781
132610b953c
141515102ad
15bbb0342d
hex77fdaf51

2013114193 has 2 divisors, whose sum is σ = 2013114194. Its totient is φ = 2013114192.

The previous prime is 2013114149. The next prime is 2013114223. The reversal of 2013114193 is 3914113102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1239884944 + 773229249 = 35212^2 + 27807^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013114193 - 213 = 2013106001 is a prime.

It is not a weakly prime, because it can be changed into another prime (2013114113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006557096 + 1006557097.

It is an arithmetic number, because the mean of its divisors is an integer number (1006557097).

Almost surely, 22013114193 is an apocalyptic number.

It is an amenable number.

2013114193 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013114193 is an equidigital number, since it uses as much as digits as its factorization.

2013114193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 2013114193 is about 44867.7411176449. The cubic root of 2013114193 is about 1262.6688606996.

Adding to 2013114193 its reverse (3914113102), we get a palindrome (5927227295).

The spelling of 2013114193 in words is "two billion, thirteen million, one hundred fourteen thousand, one hundred ninety-three".