Base | Representation |
---|---|
bin | 11101010010110111010… |
… | …111100100001001001011 |
3 | 21010110012212111220201001 |
4 | 131102313113210021023 |
5 | 230440333000234121 |
6 | 4140452015435431 |
7 | 265305006014656 |
oct | 35226727441113 |
9 | 7113185456631 |
10 | 2013121102411 |
11 | 70683a420281 |
12 | 2861a6225b77 |
13 | 117ab4a579b3 |
14 | 6d61534089d |
15 | 37574da1991 |
hex | 1d4b75e424b |
2013121102411 has 2 divisors, whose sum is σ = 2013121102412. Its totient is φ = 2013121102410.
The previous prime is 2013121102361. The next prime is 2013121102429. The reversal of 2013121102411 is 1142011213102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013121102411 - 27 = 2013121102283 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013121102471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006560551205 + 1006560551206.
It is an arithmetic number, because the mean of its divisors is an integer number (1006560551206).
Almost surely, 22013121102411 is an apocalyptic number.
2013121102411 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013121102411 is an equidigital number, since it uses as much as digits as its factorization.
2013121102411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2013121102411 its reverse (1142011213102), we get a palindrome (3155132315513).
The spelling of 2013121102411 in words is "two trillion, thirteen billion, one hundred twenty-one million, one hundred two thousand, four hundred eleven".
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