Base | Representation |
---|---|
bin | 1001001001111001010111… |
… | …00110001000100011101001 |
3 | 2122021112020221120110101111 |
4 | 10210330223212020203221 |
5 | 10114312241220230121 |
6 | 110452055421550321 |
7 | 4145301654162106 |
oct | 444745346104351 |
9 | 78245227513344 |
10 | 20131243133161 |
11 | 6461680a23546 |
12 | 23116a07153a1 |
13 | b304a28a2704 |
14 | 4d8500883aad |
15 | 24d9d6e052e1 |
hex | 124f2b9888e9 |
20131243133161 has 2 divisors, whose sum is σ = 20131243133162. Its totient is φ = 20131243133160.
The previous prime is 20131243133117. The next prime is 20131243133303. The reversal of 20131243133161 is 16133134213102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12967697942761 + 7163545190400 = 3601069^2 + 2676480^2 .
It is a cyclic number.
It is not a de Polignac number, because 20131243133161 - 27 = 20131243133033 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131243133761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065621566580 + 10065621566581.
It is an arithmetic number, because the mean of its divisors is an integer number (10065621566581).
Almost surely, 220131243133161 is an apocalyptic number.
It is an amenable number.
20131243133161 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131243133161 is an equidigital number, since it uses as much as digits as its factorization.
20131243133161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 20131243133161 its reverse (16133134213102), we get a palindrome (36264377346263).
The spelling of 20131243133161 in words is "twenty trillion, one hundred thirty-one billion, two hundred forty-three million, one hundred thirty-three thousand, one hundred sixty-one".
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