Base | Representation |
---|---|
bin | 1001001001111001010111… |
… | …00110001000100101110111 |
3 | 2122021112020221120110120202 |
4 | 10210330223212020211313 |
5 | 10114312241220231203 |
6 | 110452055421551115 |
7 | 4145301654162401 |
oct | 444745346104567 |
9 | 78245227513522 |
10 | 20131243133303 |
11 | 6461680a23665 |
12 | 23116a071549b |
13 | b304a28a27b3 |
14 | 4d8500883b71 |
15 | 24d9d6e05388 |
hex | 124f2b988977 |
20131243133303 has 2 divisors, whose sum is σ = 20131243133304. Its totient is φ = 20131243133302.
The previous prime is 20131243133161. The next prime is 20131243133357. The reversal of 20131243133303 is 30333134213102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20131243133303 - 222 = 20131238938999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131243133383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065621566651 + 10065621566652.
It is an arithmetic number, because the mean of its divisors is an integer number (10065621566652).
Almost surely, 220131243133303 is an apocalyptic number.
20131243133303 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131243133303 is an equidigital number, since it uses as much as digits as its factorization.
20131243133303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 20131243133303 its reverse (30333134213102), we get a palindrome (50464377346405).
The spelling of 20131243133303 in words is "twenty trillion, one hundred thirty-one billion, two hundred forty-three million, one hundred thirty-three thousand, three hundred three".
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