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201312551376247 is a prime number
BaseRepresentation
bin101101110001011110111011…
…000111010001010101110111
3222101210021212211121111011111
4231301132323013101111313
5202341301101123014442
61552053413120415451
760255231456035653
oct5561367307212567
9871707784544144
10201312551376247
11591651a0054263
121a6b387a177587
1388438cc82086c
14379d818117a63
151841904d4ab17
hexb717bb1d1577

201312551376247 has 2 divisors, whose sum is σ = 201312551376248. Its totient is φ = 201312551376246.

The previous prime is 201312551376137. The next prime is 201312551376281. The reversal of 201312551376247 is 742673155213102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201312551376247 - 27 = 201312551376119 is a prime.

It is a super-2 number, since 2×2013125513762472 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 201312551376247.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201312551376347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656275688123 + 100656275688124.

It is an arithmetic number, because the mean of its divisors is an integer number (100656275688124).

Almost surely, 2201312551376247 is an apocalyptic number.

201312551376247 is a deficient number, since it is larger than the sum of its proper divisors (1).

201312551376247 is an equidigital number, since it uses as much as digits as its factorization.

201312551376247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2116800, while the sum is 49.

The spelling of 201312551376247 in words is "two hundred one trillion, three hundred twelve billion, five hundred fifty-one million, three hundred seventy-six thousand, two hundred forty-seven".