Base | Representation |
---|---|
bin | 1001001001111001011111… |
… | …01010001011010101101111 |
3 | 2122021112102200211210110021 |
4 | 10210330233222023111233 |
5 | 10114312411143130444 |
6 | 110452110255023011 |
7 | 4145303442461062 |
oct | 444745752132557 |
9 | 78245380753407 |
10 | 20131311301999 |
11 | 6461706453827 |
12 | 23116bb50aa67 |
13 | b304b3a4c8c1 |
14 | 4d850994a8d9 |
15 | 24d9dcdbd584 |
hex | 124f2fa8b56f |
20131311301999 has 2 divisors, whose sum is σ = 20131311302000. Its totient is φ = 20131311301998.
The previous prime is 20131311301987. The next prime is 20131311302017. The reversal of 20131311301999 is 99910311313102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20131311301999 - 211 = 20131311299951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20131311301099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065655650999 + 10065655651000.
It is an arithmetic number, because the mean of its divisors is an integer number (10065655651000).
Almost surely, 220131311301999 is an apocalyptic number.
20131311301999 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131311301999 is an equidigital number, since it uses as much as digits as its factorization.
20131311301999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366, while the sum is 43.
The spelling of 20131311301999 in words is "twenty trillion, one hundred thirty-one billion, three hundred eleven million, three hundred one thousand, nine hundred ninety-nine".
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