Base | Representation |
---|---|
bin | 11101010010110111111… |
… | …110000101110111011011 |
3 | 21010110020120112000202022 |
4 | 131102313332011313123 |
5 | 230440343041431021 |
6 | 4140453020125055 |
7 | 265305160610606 |
oct | 35226776056733 |
9 | 7113216460668 |
10 | 2013131202011 |
11 | 706845099256 |
12 | 2861a969678b |
13 | 117ab6b829a7 |
14 | 6d61680d33d |
15 | 37575be91ab |
hex | 1d4b7f85ddb |
2013131202011 has 2 divisors, whose sum is σ = 2013131202012. Its totient is φ = 2013131202010.
The previous prime is 2013131202001. The next prime is 2013131202013. The reversal of 2013131202011 is 1102021313102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013131202011 - 26 = 2013131201947 is a prime.
Together with 2013131202013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2013131202013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006565601005 + 1006565601006.
It is an arithmetic number, because the mean of its divisors is an integer number (1006565601006).
Almost surely, 22013131202011 is an apocalyptic number.
2013131202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013131202011 is an equidigital number, since it uses as much as digits as its factorization.
2013131202011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2013131202011 its reverse (1102021313102), we get a palindrome (3115152515113).
The spelling of 2013131202011 in words is "two trillion, thirteen billion, one hundred thirty-one million, two hundred two thousand, eleven".
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