Base | Representation |
---|---|
bin | 101101110001100000010001… |
… | …011101110000001000110001 |
3 | 222101210102121210122210102221 |
4 | 231301200101131300020301 |
5 | 202341312033012011004 |
6 | 1552054212552041041 |
7 | 60255312410053624 |
oct | 5561402135601061 |
9 | 871712553583387 |
10 | 201314000110129 |
11 | 591658738a9495 |
12 | 1a6b4003393181 |
13 | 8843aa0a0334a |
14 | 379d9146b3dbb |
15 | 184198c11a354 |
hex | b71811770231 |
201314000110129 has 2 divisors, whose sum is σ = 201314000110130. Its totient is φ = 201314000110128.
The previous prime is 201314000110039. The next prime is 201314000110151. The reversal of 201314000110129 is 921011000413102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 197231688966400 + 4082311143729 = 14043920^2 + 2020473^2 .
It is a cyclic number.
It is not a de Polignac number, because 201314000110129 - 29 = 201314000109617 is a prime.
It is not a weakly prime, because it can be changed into another prime (201314000110169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100657000055064 + 100657000055065.
It is an arithmetic number, because the mean of its divisors is an integer number (100657000055065).
Almost surely, 2201314000110129 is an apocalyptic number.
It is an amenable number.
201314000110129 is a deficient number, since it is larger than the sum of its proper divisors (1).
201314000110129 is an equidigital number, since it uses as much as digits as its factorization.
201314000110129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 201314000110129 in words is "two hundred one trillion, three hundred fourteen billion, one hundred ten thousand, one hundred twenty-nine".
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