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2013142214333 is a prime number
BaseRepresentation
bin11101010010111000101…
…000000110011010111101
321010110021100020111211002
4131102320220012122331
5230440403401324313
64140454052140045
7265305353324525
oct35227050063275
97113240214732
102013142214333
1170685032aa48
122861b1307625
13117ab923a263
146d618078685
1537576b72058
hex1d4b8a066bd

2013142214333 has 2 divisors, whose sum is σ = 2013142214334. Its totient is φ = 2013142214332.

The previous prime is 2013142214323. The next prime is 2013142214339. The reversal of 2013142214333 is 3334122413102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1347185026489 + 665957187844 = 1160683^2 + 816062^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013142214333 - 26 = 2013142214269 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013142214296 and 2013142214305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013142214339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006571107166 + 1006571107167.

It is an arithmetic number, because the mean of its divisors is an integer number (1006571107167).

Almost surely, 22013142214333 is an apocalyptic number.

It is an amenable number.

2013142214333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013142214333 is an equidigital number, since it uses as much as digits as its factorization.

2013142214333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 2013142214333 its reverse (3334122413102), we get a palindrome (5347264627435).

The spelling of 2013142214333 in words is "two trillion, thirteen billion, one hundred forty-two million, two hundred fourteen thousand, three hundred thirty-three".