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20132024211011 is a prime number
BaseRepresentation
bin1001001001111010110100…
…01001101101011001000011
32122021121021101022022202202
410210331122021231121003
510114320341144223021
6110452305123103415
74145330220216026
oct444753211553103
978247241268682
1020132024211011
116461a4190a929
12231187a211b6b
13b3059865b95b
144d85764c51bd
1524da30790a0b
hex124f5a26d643

20132024211011 has 2 divisors, whose sum is σ = 20132024211012. Its totient is φ = 20132024211010.

The previous prime is 20132024210993. The next prime is 20132024211031. The reversal of 20132024211011 is 11011242023102.

It is an a-pointer prime, because the next prime (20132024211031) can be obtained adding 20132024211011 to its sum of digits (20).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20132024211011 - 218 = 20132023948867 is a prime.

It is not a weakly prime, because it can be changed into another prime (20132024211031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066012105505 + 10066012105506.

It is an arithmetic number, because the mean of its divisors is an integer number (10066012105506).

Almost surely, 220132024211011 is an apocalyptic number.

20132024211011 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132024211011 is an equidigital number, since it uses as much as digits as its factorization.

20132024211011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 20132024211011 its reverse (11011242023102), we get a palindrome (31143266234113).

The spelling of 20132024211011 in words is "twenty trillion, one hundred thirty-two billion, twenty-four million, two hundred eleven thousand, eleven".