Base | Representation |
---|---|
bin | 1001001001111010110100… |
… | …01001101101011001000011 |
3 | 2122021121021101022022202202 |
4 | 10210331122021231121003 |
5 | 10114320341144223021 |
6 | 110452305123103415 |
7 | 4145330220216026 |
oct | 444753211553103 |
9 | 78247241268682 |
10 | 20132024211011 |
11 | 6461a4190a929 |
12 | 231187a211b6b |
13 | b3059865b95b |
14 | 4d85764c51bd |
15 | 24da30790a0b |
hex | 124f5a26d643 |
20132024211011 has 2 divisors, whose sum is σ = 20132024211012. Its totient is φ = 20132024211010.
The previous prime is 20132024210993. The next prime is 20132024211031. The reversal of 20132024211011 is 11011242023102.
It is an a-pointer prime, because the next prime (20132024211031) can be obtained adding 20132024211011 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20132024211011 - 218 = 20132023948867 is a prime.
It is not a weakly prime, because it can be changed into another prime (20132024211031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066012105505 + 10066012105506.
It is an arithmetic number, because the mean of its divisors is an integer number (10066012105506).
Almost surely, 220132024211011 is an apocalyptic number.
20132024211011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132024211011 is an equidigital number, since it uses as much as digits as its factorization.
20132024211011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 20132024211011 its reverse (11011242023102), we get a palindrome (31143266234113).
The spelling of 20132024211011 in words is "twenty trillion, one hundred thirty-two billion, twenty-four million, two hundred eleven thousand, eleven".
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