Base | Representation |
---|---|
bin | 11101010010111101011… |
… | …100101001111011001111 |
3 | 21010110110222102221020122 |
4 | 131102331130221323033 |
5 | 230441040103200421 |
6 | 4140510101535155 |
7 | 265310355000236 |
oct | 35227534517317 |
9 | 7113428387218 |
10 | 2013223100111 |
11 | 706891a566a3 |
12 | 2862144144bb |
13 | 117accc1a872 |
14 | 6d624ad1b1d |
15 | 3757dced2ab |
hex | 1d4bd729ecf |
2013223100111 has 2 divisors, whose sum is σ = 2013223100112. Its totient is φ = 2013223100110.
The previous prime is 2013223100099. The next prime is 2013223100129. The reversal of 2013223100111 is 1110013223102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013223100111 - 26 = 2013223100047 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2013223100111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013223105111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006611550055 + 1006611550056.
It is an arithmetic number, because the mean of its divisors is an integer number (1006611550056).
Almost surely, 22013223100111 is an apocalyptic number.
2013223100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013223100111 is an equidigital number, since it uses as much as digits as its factorization.
2013223100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2013223100111 its reverse (1110013223102), we get a palindrome (3123236323213).
The spelling of 2013223100111 in words is "two trillion, thirteen billion, two hundred twenty-three million, one hundred thousand, one hundred eleven".
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