Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000001101110001111 |
3 | 1220222001200002112201 |
4 | 102233333001232033 |
5 | 312212343412421 |
6 | 13125415142331 |
7 | 1311620416501 |
oct | 225777015617 |
9 | 56861602481 |
10 | 20132404111 |
11 | 85a1243206 |
12 | 3a9a3749a7 |
13 | 1b8ac55771 |
14 | d8db0dd71 |
15 | 7cc6c1b91 |
hex | 4affc1b8f |
20132404111 has 2 divisors, whose sum is σ = 20132404112. Its totient is φ = 20132404110.
The previous prime is 20132404069. The next prime is 20132404141. The reversal of 20132404111 is 11140423102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20132404111 - 213 = 20132395919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132404141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066202055 + 10066202056.
It is an arithmetic number, because the mean of its divisors is an integer number (10066202056).
Almost surely, 220132404111 is an apocalyptic number.
20132404111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132404111 is an equidigital number, since it uses as much as digits as its factorization.
20132404111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 20132404111 its reverse (11140423102), we get a palindrome (31272827213).
The spelling of 20132404111 in words is "twenty billion, one hundred thirty-two million, four hundred four thousand, one hundred eleven".
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