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2013241333 is a prime number
BaseRepresentation
bin111011111111111…
…1001111111110101
312012022021020220211
41313333321333311
513110342210313
6531434425421
7100614161155
oct16777717765
95168236824
102013241333
11943471014
12482292271
1326113237c
14151544765
15bbb2ae3d
hex77ff9ff5

2013241333 has 2 divisors, whose sum is σ = 2013241334. Its totient is φ = 2013241332.

The previous prime is 2013241319. The next prime is 2013241343. The reversal of 2013241333 is 3331423102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1319287684 + 693953649 = 36322^2 + 26343^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013241333 - 29 = 2013240821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013241343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006620666 + 1006620667.

It is an arithmetic number, because the mean of its divisors is an integer number (1006620667).

Almost surely, 22013241333 is an apocalyptic number.

It is an amenable number.

2013241333 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013241333 is an equidigital number, since it uses as much as digits as its factorization.

2013241333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 2013241333 is about 44869.1579261301. The cubic root of 2013241333 is about 1262.6954417948.

Adding to 2013241333 its reverse (3331423102), we get a palindrome (5344664435).

The spelling of 2013241333 in words is "two billion, thirteen million, two hundred forty-one thousand, three hundred thirty-three".