Base | Representation |
---|---|
bin | 1001001001111011100110… |
… | …01011110110100110000101 |
3 | 2122021122100122121011000022 |
4 | 10210331303023312212011 |
5 | 10114322221204002042 |
6 | 110452414525024525 |
7 | 4145343510125441 |
oct | 444756313664605 |
9 | 78248318534008 |
10 | 20132444203397 |
11 | 64621379a0379 |
12 | 23119769b5145 |
13 | b30634680066 |
14 | 4d85b61b1821 |
15 | 24da575a2cd2 |
hex | 124f732f6985 |
20132444203397 has 2 divisors, whose sum is σ = 20132444203398. Its totient is φ = 20132444203396.
The previous prime is 20132444203381. The next prime is 20132444203471. The reversal of 20132444203397 is 79330244423102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13175927177956 + 6956517025441 = 3629866^2 + 2637521^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132444203397 - 24 = 20132444203381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132444203337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066222101698 + 10066222101699.
It is an arithmetic number, because the mean of its divisors is an integer number (10066222101699).
Almost surely, 220132444203397 is an apocalyptic number.
It is an amenable number.
20132444203397 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132444203397 is an equidigital number, since it uses as much as digits as its factorization.
20132444203397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 44.
Adding to 20132444203397 its reverse (79330244423102), we get a palindrome (99462688626499).
The spelling of 20132444203397 in words is "twenty trillion, one hundred thirty-two billion, four hundred forty-four million, two hundred three thousand, three hundred ninety-seven".
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