Base | Representation |
---|---|
bin | 101101110001101111001011… |
… | …010100011001010100010011 |
3 | 222101211221221002010222222002 |
4 | 231301233023110121110103 |
5 | 202342042321244341202 |
6 | 1552105420540104215 |
7 | 60256420106315345 |
oct | 5561571324312423 |
9 | 871757832128862 |
10 | 201330003121427 |
11 | 59171636110764 |
12 | 1a6b712a83506b |
13 | 88454512a20bb |
14 | 37a05d1bcb295 |
15 | 18420c7008302 |
hex | b71bcb519513 |
201330003121427 has 2 divisors, whose sum is σ = 201330003121428. Its totient is φ = 201330003121426.
The previous prime is 201330003121397. The next prime is 201330003121519. The reversal of 201330003121427 is 724121300033102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201330003121427 - 28 = 201330003121171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201330003121427.
It is not a weakly prime, because it can be changed into another prime (201330003121727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665001560713 + 100665001560714.
It is an arithmetic number, because the mean of its divisors is an integer number (100665001560714).
Almost surely, 2201330003121427 is an apocalyptic number.
201330003121427 is a deficient number, since it is larger than the sum of its proper divisors (1).
201330003121427 is an equidigital number, since it uses as much as digits as its factorization.
201330003121427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 201330003121427 its reverse (724121300033102), we get a palindrome (925451303154529).
The spelling of 201330003121427 in words is "two hundred one trillion, three hundred thirty billion, three million, one hundred twenty-one thousand, four hundred twenty-seven".
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