Base | Representation |
---|---|
bin | 101101110001101111001011… |
… | …010100011001010011110101 |
3 | 222101211221221002010222220222 |
4 | 231301233023110121103311 |
5 | 202342042321244341042 |
6 | 1552105420540104125 |
7 | 60256420106315303 |
oct | 5561571324312365 |
9 | 871757832128828 |
10 | 201330003121397 |
11 | 59171636110737 |
12 | 1a6b712a835045 |
13 | 88454512a2097 |
14 | 37a05d1bcb273 |
15 | 18420c70082d2 |
hex | b71bcb5194f5 |
201330003121397 has 2 divisors, whose sum is σ = 201330003121398. Its totient is φ = 201330003121396.
The previous prime is 201330003121393. The next prime is 201330003121427. The reversal of 201330003121397 is 793121300033102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 151403328815236 + 49926674306161 = 12304606^2 + 7065881^2 .
It is a cyclic number.
It is not a de Polignac number, because 201330003121397 - 22 = 201330003121393 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201330003121393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665001560698 + 100665001560699.
It is an arithmetic number, because the mean of its divisors is an integer number (100665001560699).
Almost surely, 2201330003121397 is an apocalyptic number.
It is an amenable number.
201330003121397 is a deficient number, since it is larger than the sum of its proper divisors (1).
201330003121397 is an equidigital number, since it uses as much as digits as its factorization.
201330003121397 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20412, while the sum is 35.
Adding to 201330003121397 its reverse (793121300033102), we get a palindrome (994451303154499).
The spelling of 201330003121397 in words is "two hundred one trillion, three hundred thirty billion, three million, one hundred twenty-one thousand, three hundred ninety-seven".
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