Base | Representation |
---|---|
bin | 1001001001111100101001… |
… | …11111001110110110011111 |
3 | 2122021200211011201200001012 |
4 | 10210332110333032312133 |
5 | 10114324401344221343 |
6 | 110452551104205435 |
7 | 4145363534420324 |
oct | 444762477166637 |
9 | 78250734650035 |
10 | 20133011320223 |
11 | 64623a902966a |
12 | 2311ab490987b |
13 | b306c5004549 |
14 | 4d862b638b4b |
15 | 24da8c277718 |
hex | 124f94fced9f |
20133011320223 has 2 divisors, whose sum is σ = 20133011320224. Its totient is φ = 20133011320222.
The previous prime is 20133011320189. The next prime is 20133011320237. The reversal of 20133011320223 is 32202311033102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20133011320223 - 210 = 20133011319199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20133011320423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066505660111 + 10066505660112.
It is an arithmetic number, because the mean of its divisors is an integer number (10066505660112).
Almost surely, 220133011320223 is an apocalyptic number.
20133011320223 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133011320223 is an equidigital number, since it uses as much as digits as its factorization.
20133011320223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 20133011320223 its reverse (32202311033102), we get a palindrome (52335322353325).
The spelling of 20133011320223 in words is "twenty trillion, one hundred thirty-three billion, eleven million, three hundred twenty thousand, two hundred twenty-three".
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