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2013305335 = 5402661067
BaseRepresentation
bin111100000000000…
…1001100111110111
312012022101111201021
41320000021213313
513110401232320
6531440042011
7100614545566
oct17000114767
95168344637
102013305335
11943505108
12482303307
13261155542
1415155dbdd
15bbb3edaa
hex780099f7

2013305335 has 4 divisors (see below), whose sum is σ = 2415966408. Its totient is φ = 1610644264.

The previous prime is 2013305317. The next prime is 2013305339. The reversal of 2013305335 is 5335033102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013305335 - 215 = 2013272567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013305339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201330529 + ... + 201330538.

It is an arithmetic number, because the mean of its divisors is an integer number (603991602).

Almost surely, 22013305335 is an apocalyptic number.

2013305335 is a deficient number, since it is larger than the sum of its proper divisors (402661073).

2013305335 is an equidigital number, since it uses as much as digits as its factorization.

2013305335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402661072.

The product of its (nonzero) digits is 4050, while the sum is 25.

The square root of 2013305335 is about 44869.8711275172. The cubic root of 2013305335 is about 1262.7088222369.

Adding to 2013305335 its reverse (5335033102), we get a palindrome (7348338437).

The spelling of 2013305335 in words is "two billion, thirteen million, three hundred five thousand, three hundred thirty-five".

Divisors: 1 5 402661067 2013305335