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20133315551 = 99120316161
BaseRepresentation
bin10010110000000010…
…100000001111011111
31220222010101101210202
4102300002200033133
5312213112044201
613125450454115
71311631233656
oct226002401737
956863341722
1020133315551
1185a1805a68
123a9a73433b
131b8b1b458b
14d8dcaa19d
157cc801c6b
hex4b00a03df

20133315551 has 4 divisors (see below), whose sum is σ = 20153632704. Its totient is φ = 20112998400.

The previous prime is 20133315547. The next prime is 20133315607. The reversal of 20133315551 is 15551333102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15551333102 = 27775666551.

It is a cyclic number.

It is not a de Polignac number, because 20133315551 - 22 = 20133315547 is a prime.

It is a super-2 number, since 2×201333155512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133317551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10157090 + ... + 10159071.

It is an arithmetic number, because the mean of its divisors is an integer number (5038408176).

Almost surely, 220133315551 is an apocalyptic number.

20133315551 is a deficient number, since it is larger than the sum of its proper divisors (20317153).

20133315551 is an equidigital number, since it uses as much as digits as its factorization.

20133315551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20317152.

The product of its (nonzero) digits is 6750, while the sum is 29.

Adding to 20133315551 its reverse (15551333102), we get a palindrome (35684648653).

The spelling of 20133315551 in words is "twenty billion, one hundred thirty-three million, three hundred fifteen thousand, five hundred fifty-one".

Divisors: 1 991 20316161 20133315551