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20133411242053 is a prime number
BaseRepresentation
bin1001001001111101011001…
…10100110100000001000101
32122021201212001020210122211
410210332230310310001011
510114331211234221203
6110453054512023421
74145406461615224
oct444765464640105
978251761223584
1020133411242053
11646259385087a
122311ba6831b71
13b30759b19395
144d86687bccbb
1524dab2422c6d
hex124facd34045

20133411242053 has 2 divisors, whose sum is σ = 20133411242054. Its totient is φ = 20133411242052.

The previous prime is 20133411241907. The next prime is 20133411242081. The reversal of 20133411242053 is 35024211433102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15781606376449 + 4351804865604 = 3972607^2 + 2086098^2 .

It is a cyclic number.

It is not a de Polignac number, because 20133411242053 - 213 = 20133411233861 is a prime.

It is a super-2 number, since 2×201334112420532 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20133411342053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066705621026 + 10066705621027.

It is an arithmetic number, because the mean of its divisors is an integer number (10066705621027).

Almost surely, 220133411242053 is an apocalyptic number.

It is an amenable number.

20133411242053 is a deficient number, since it is larger than the sum of its proper divisors (1).

20133411242053 is an equidigital number, since it uses as much as digits as its factorization.

20133411242053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 20133411242053 its reverse (35024211433102), we get a palindrome (55157622675155).

The spelling of 20133411242053 in words is "twenty trillion, one hundred thirty-three billion, four hundred eleven million, two hundred forty-two thousand, fifty-three".