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201334305397 is a prime number
BaseRepresentation
bin1011101110000001110…
…1011011001001110101
3201020200100000102101211
42323200131123021311
511244313040233042
6232254112521421
720355152234131
oct2734035331165
9636610012354
10201334305397
1178426a6a635
123302a550271
1315ca78a89b4
149a5d3b23c1
15538568e017
hex2ee075b275

201334305397 has 2 divisors, whose sum is σ = 201334305398. Its totient is φ = 201334305396.

The previous prime is 201334305383. The next prime is 201334305433. The reversal of 201334305397 is 793503433102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138052374916 + 63281930481 = 371554^2 + 251559^2 .

It is a cyclic number.

It is not a de Polignac number, because 201334305397 - 27 = 201334305269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201334305197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100667152698 + 100667152699.

It is an arithmetic number, because the mean of its divisors is an integer number (100667152699).

Almost surely, 2201334305397 is an apocalyptic number.

It is an amenable number.

201334305397 is a deficient number, since it is larger than the sum of its proper divisors (1).

201334305397 is an equidigital number, since it uses as much as digits as its factorization.

201334305397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 40.

Adding to 201334305397 its reverse (793503433102), we get a palindrome (994837738499).

The spelling of 201334305397 in words is "two hundred one billion, three hundred thirty-four million, three hundred five thousand, three hundred ninety-seven".