Base | Representation |
---|---|
bin | 11101010011000100110… |
… | …001001100010110010001 |
3 | 21010110210112120001121222 |
4 | 131103010301030112101 |
5 | 230441313024040442 |
6 | 4140530210254425 |
7 | 265313405663645 |
oct | 35230461142621 |
9 | 7113715501558 |
10 | 2013345924497 |
11 | 706945317456 |
12 | 286249587415 |
13 | 117b1c4c320b |
14 | 6d637144c25 |
15 | 375899b08d2 |
hex | 1d4c4c4c591 |
2013345924497 has 2 divisors, whose sum is σ = 2013345924498. Its totient is φ = 2013345924496.
The previous prime is 2013345924493. The next prime is 2013345924637. The reversal of 2013345924497 is 7944295433102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1565141115136 + 448204809361 = 1251056^2 + 669481^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013345924497 - 22 = 2013345924493 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013345924493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006672962248 + 1006672962249.
It is an arithmetic number, because the mean of its divisors is an integer number (1006672962249).
Almost surely, 22013345924497 is an apocalyptic number.
It is an amenable number.
2013345924497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013345924497 is an equidigital number, since it uses as much as digits as its factorization.
2013345924497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 53.
The spelling of 2013345924497 in words is "two trillion, thirteen billion, three hundred forty-five million, nine hundred twenty-four thousand, four hundred ninety-seven".
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