Base | Representation |
---|---|
bin | 11101010011000101000… |
… | …000101111100111111111 |
3 | 21010110210211020011202011 |
4 | 131103011000233213333 |
5 | 230441320100014101 |
6 | 4140530433512051 |
7 | 265313455433146 |
oct | 35230500574777 |
9 | 7113724204664 |
10 | 2013350001151 |
11 | 706947651295 |
12 | 28624aa12627 |
13 | 117b202bc938 |
14 | 6d6378c675d |
15 | 3758a018751 |
hex | 1d4c502f9ff |
2013350001151 has 2 divisors, whose sum is σ = 2013350001152. Its totient is φ = 2013350001150.
The previous prime is 2013350001101. The next prime is 2013350001167. The reversal of 2013350001151 is 1511000533102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013350001151 - 219 = 2013349476863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013350001101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006675000575 + 1006675000576.
It is an arithmetic number, because the mean of its divisors is an integer number (1006675000576).
Almost surely, 22013350001151 is an apocalyptic number.
2013350001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013350001151 is an equidigital number, since it uses as much as digits as its factorization.
2013350001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 2013350001151 its reverse (1511000533102), we get a palindrome (3524350534253).
The spelling of 2013350001151 in words is "two trillion, thirteen billion, three hundred fifty million, one thousand, one hundred fifty-one".
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