2013401301217 has 2 divisors, whose sum is σ = 2013401301218. Its totient is φ = 2013401301216.

The previous prime is 2013401301167. The next prime is 2013401301257. The reversal of 2013401301217 is 7121031043102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1876705465041 + 136695836176 = 1369929^2 + 369724^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013401301217 - 2³¹ = 2011253817569 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013401301191 and 2013401301200.

It is not a weakly prime, because it can be changed into another prime (2013401301257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006700650608 + 1006700650609.

It is an arithmetic number, because the mean of its divisors is an integer number (1006700650609).

Almost surely, 2^{2013401301217} is an apocalyptic number.

It is an amenable number.

2013401301217 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013401301217 is an equidigital number, since it uses as much as digits as its factorization.

2013401301217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 2013401301217 its reverse (7121031043102), we get a palindrome (9134432344319).

The spelling of 2013401301217 in words is "two trillion, thirteen billion, four hundred one million, three hundred one thousand, two hundred seventeen".