Base | Representation |
---|---|
bin | 1011101110000011001… |
… | …1111010010111010010 |
3 | 201020200202002220211100 |
4 | 2323200303322113102 |
5 | 11244321042403102 |
6 | 232254443125230 |
7 | 20355253315545 |
oct | 2734063722722 |
9 | 636622086740 |
10 | 201340200402 |
11 | 7842a326640 |
12 | 33030513816 |
13 | 15ca8b90c73 |
14 | 9a600a885c |
15 | 5385e55a1c |
hex | 2ee0cfa5d2 |
201340200402 has 24 divisors (see below), whose sum is σ = 475895019600. Its totient is φ = 61012181880.
The previous prime is 201340200379. The next prime is 201340200409. The reversal of 201340200402 is 204002043102.
201340200402 is a `hidden beast` number, since 20 + 1 + 3 + 40 + 200 + 402 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (201340200409) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 508434652 + ... + 508435047.
It is an arithmetic number, because the mean of its divisors is an integer number (19828959150).
Almost surely, 2201340200402 is an apocalyptic number.
201340200402 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
201340200402 is an abundant number, since it is smaller than the sum of its proper divisors (274554819198).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201340200402 is a wasteful number, since it uses less digits than its factorization.
201340200402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1016869718 (or 1016869715 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 18.
Adding to 201340200402 its reverse (204002043102), we get a palindrome (405342243504).
The spelling of 201340200402 in words is "two hundred one billion, three hundred forty million, two hundred thousand, four hundred two".
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