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201340213381 is a prime number
BaseRepresentation
bin1011101110000011001…
…1111101100010000101
3201020200202010120122001
42323200303331202011
511244321043312011
6232254443305301
720355253401436
oct2734063754205
9636622116561
10201340213381
117842a33536a
123303051b231
1315ca8b96b48
149a600ad48d
155385e597c1
hex2ee0cfd885

201340213381 has 2 divisors, whose sum is σ = 201340213382. Its totient is φ = 201340213380.

The previous prime is 201340213367. The next prime is 201340213387. The reversal of 201340213381 is 183312043102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183925188225 + 17415025156 = 428865^2 + 131966^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201340213381 is a prime.

It is a super-2 number, since 2×2013402133812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201340213387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670106690 + 100670106691.

It is an arithmetic number, because the mean of its divisors is an integer number (100670106691).

Almost surely, 2201340213381 is an apocalyptic number.

It is an amenable number.

201340213381 is a deficient number, since it is larger than the sum of its proper divisors (1).

201340213381 is an equidigital number, since it uses as much as digits as its factorization.

201340213381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 201340213381 its reverse (183312043102), we get a palindrome (384652256483).

The spelling of 201340213381 in words is "two hundred one billion, three hundred forty million, two hundred thirteen thousand, three hundred eighty-one".