Base | Representation |
---|---|
bin | 1011101110000011010… |
… | …0000010001011110101 |
3 | 201020200202011112202211 |
4 | 2323200310002023311 |
5 | 11244321044414222 |
6 | 232254443533421 |
7 | 20355253511131 |
oct | 2734064021365 |
9 | 636622145684 |
10 | 201340232437 |
11 | 7842a348713 |
12 | 3303052a271 |
13 | 15ca8ba2716 |
14 | 9a600b63c1 |
15 | 5385e60277 |
hex | 2ee0d022f5 |
201340232437 has 2 divisors, whose sum is σ = 201340232438. Its totient is φ = 201340232436.
The previous prime is 201340232407. The next prime is 201340232449. The reversal of 201340232437 is 734232043102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 178008891921 + 23331340516 = 421911^2 + 152746^2 .
It is a cyclic number.
It is not a de Polignac number, because 201340232437 - 235 = 166980494069 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201340232399 and 201340232408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201340232407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670116218 + 100670116219.
It is an arithmetic number, because the mean of its divisors is an integer number (100670116219).
Almost surely, 2201340232437 is an apocalyptic number.
It is an amenable number.
201340232437 is a deficient number, since it is larger than the sum of its proper divisors (1).
201340232437 is an equidigital number, since it uses as much as digits as its factorization.
201340232437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 31.
Adding to 201340232437 its reverse (734232043102), we get a palindrome (935572275539).
The spelling of 201340232437 in words is "two hundred one billion, three hundred forty million, two hundred thirty-two thousand, four hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •